7(4^x+3)=35

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Solution for 7(4^x+3)=35 equation: 



7(4^x+3)=35

We move all terms to the left:

7(4^x+3)-(35)=0

We multiply parentheses

28x+21-35=0

We add all the numbers together, and all the variables

28x-14=0

We move all terms containing x to the left, all other terms to the right

28x=14

x=14/28

x=1/2

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